1>2

[Supergrunch]

In a similar vein to the 0.999rec=1 thread, I shall post the proof that 1>2

1/2 > 1/4
log(1/2) > log(1/4)
log(1/2) > log[(1/2)squared]
log(1/2) > 2 log(1/2)
1 > 2

Can anyone find the error?

[kopo]

I think if the ground number (whatever you guys call it) =a is between -1 and 1 or something you need to change the > to <. Might not be intirely correct.

[The Peeps]

Here's the error... 1, 2, 3.

Good day to you...

[kopo]

Here's the error... 1, 2, 3.

Good day to you...
might be missing something here but .... eh?

[Din]

I hve no idea what this thread is about... So WTF?

[Supergrunch]

I think if the ground number (whatever you guys call it) =a is between -1 and 1 or something you need to change the > to <. Might not be intirely correct.

Congratulations!

I thought it would be a little more than half an hour before someone got it.

EDIT: Well, you're pretty much right.

[kopo]

I hve no idea what this thread is about... So WTF?
Either you're -16 or you haven't paying much attention in math. Or you're doing a non-math course, which would make more sense. Or... you're an alien.
All bow for our new alien overlords *bows*

Edit
Congratulations!

I thought it would be a little more than half an hour before someone got it.

actually i haven't read it from the moment you posted it, took me 2 mins to figure out :wink:

[The Peeps]

1, 2, 3

1 then 2 then 3

1 is less than 2 :P don't really need more convincing than that surely?
1, 2, 3, 4, 5, 6, 7.... I could go on and on and on and on and on and on and on and on and on and on and on.

[Din]

Or... you're an alien.
All bow for our new alien overlords *bows*
Shit, you're on to me...:heh:

[kopo]

1, 2, 3

1 then 2 then 3

1 is less than 2 :P don't really need more convincing than that surely?
1, 2, 3, 4, 5, 6, 7.... I could go on and on and on and on and on and on and on and on and on and on and on.
but the question was to find the error in the prove that had been given. And the only way your answer would be correct is if you proved it.